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Given the two concentration of HCN $(K_{a} = 10^{- 9})$ are 0.1 M and 0.001 M respectively. What will be the ratio of degree of dissociation?

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0.1

0.01

0.003

answer is B.

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Detailed Solution

$α = \sqrt{\frac{k_{a}}{C}}$

$\frac{α_{1}}{α_{2}} = \sqrt{\frac{C_{2}}{C_{1}}} = \sqrt{\frac{10^{- 3}}{10^{- 1}}} = 0.1$

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