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Q.

Given this set of quantum numbers for a multielectron atom 2, 0, 0, and -1/2. The next higher allowed set of n and l for this atom in its ground state

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a

n=3, l=0

b

n=3, l=1

c

n=2, l=1

d

n=2, l=0

answer is B.

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Detailed Solution

For the quantum numbers 

2   ,0    ,0    ,1/2  it is 2s- orbital. 

possible lelctronic configuration : : 2s1 2s2.

next possible orbital is : 2p orbital 

which has n=2 and l=1.

 

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