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Given two lines
$\begin{array}{l} L_{1} : \frac{x - 2023}{a_{1}} = \frac{y - 2022}{b_{1}} = \frac{z + 2021}{c_{1}}, \\ L_{2} : \frac{x - 2023}{a_{2}} = \frac{y - 2022}{b_{2}} = \frac{z - 2021}{c_{2}} \end{array}$
And $L_{1}, L_{2}$ are parallel lines ( $a_{i}, b_{i}, c_{i} \neq 0, \forall i = 1, 2$ ) and $a_{1}, b_{1}, c_{1}$ are direction cosines of $L_{1},$ and $a_{2}, b_{2}, c_{2}$ are direction cosines of $L_{2}$ . And $\frac{a_{1}}{a_{2}} = \frac{b_{1}}{b_{2}} = \frac{c_{1}}{c_{2}} = λ, w h e r e λ \in R - {0}$
which of the following options is/are CORRECT?

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The value of $\lim_{x \to λ} \frac{x^{2} - 4}{x - 2}$ can be 2022

The value of $\lim_{x \to λ} \frac{x^{2} - 4}{x - 2}$ can be 1

The value of $\lim_{x \to λ} \frac{x^{2} - 4}{x - 2}$ can be 2023

The value of $\lim_{x \to λ} \frac{x^{2} - 4}{x - 2}$ can be 3

answer is C, D.

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Detailed Solution

$λ = 1 o r - 1$

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