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Given v=0.6-0.3.t (in SI units).Then the initial velocity and acceleration are

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$- 0.3 m s^{- 1}, 0.6 m s^{- 2}$

$0.6 m s^{- 1}, - 0.3 m s^{- 2}$

$- 0.6 m s^{- 1}, 0.3 m s^{- 2}$

$0.3 m s^{- 1}, 0.6 m s^{- 2}$

answer is A.

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Detailed Solution

$V = u + a t u = 0.6 m / s a = - 0.3 m / s^{2}$

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