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Q.

Given $X ⟶ product (1st order reaction)$
$conc. (mol/lit) 0.01 0.0025$
time (min) 0 40
Initial rate of reaction $(i n m o l / l / m i n)$

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a

$3.43 \times 10^{- 4}$

b

$1.73 \times 10^{- 4}$

c

$3.43 \times 10^{- 5}$

answer is A.

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Detailed Solution

$k = \frac{1}{40} \ln (\frac{0.01}{0.0025})$

$r_{0} = [\frac{1}{40} \ln 4] \times 0.01$

$= 3.43 \times 10^{- 4}$

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