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Q.

Given $y = \sin 2 x$ , then find $\frac{dy}{dx}$

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a

$\frac{\cos 2 x}{2}$

b

$2 \cos 2 x$

c

$2 \sin^{2} x$

d

$2 \cos x$

answer is C.

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Detailed Solution

$y = \sin 2 x$

$\frac{dy}{dx} = \frac{d}{dx} (\sin 2 x) = 2 \cos 2 x$

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Giveny=sin 2x, then finddydx