Glass has refractive index $μ$ with respect to air and the critical angle for a ray of light going from glass to air is $θ$ . If a ray of light is incident from air on the glass with angle of incidence $θ$ , the corresponding angle of refraction is

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$\sin^{- 1} (\frac{1}{μ^{2}})$

$\sin^{- 1} (\frac{1}{μ})$

$\sin^{- 1} (\frac{1}{\sqrt{μ}})$

$90^{\circ}$

answer is C.

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Detailed Solution

$_{a} μ_{g} = \frac{1}{sinθ} \Rightarrow μ = \frac{1}{sinθ}$ ---(1)

Now from Snell's law $μ = \frac{sini}{sinr} = \frac{sinθ}{sinr}$

$\Rightarrow sinr = \frac{sinθ}{μ}$ ---(2)

From equation (i) and (ii)

$sinr = \frac{1}{μ^{2}} \Rightarrow r = \sin^{- 1} (\frac{1}{μ^{2}})$

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