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Q.

Graphite gives Mellitic acid with conc $H N O_{3}$ . It supports the hexagonal structure of graphite. The no of carbon atoms with $S P^{2}$ hybridization in Mellitic acid is $x$ . Then $\frac{x}{2}$ is.

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answer is 6.

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Detailed Solution

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Mellitic acid is C₁₁H₄O₅ and its structure is:

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The number of sp² hybridized carbon atom is:

$x = 12 \frac{x}{2} = \frac{12}{2} = 6$

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Graphite gives Mellitic acid with conc HNO3. It supports the hexagonal structure of graphite. The no of carbon atoms with SP2 hybridization in Mellitic acid is x. Then x2 is.