Green colored ferrous sulphate solution is taken in four beakers A, B, C and D. Strips of magnesium, zinc, copper and silver are dipped in A, B, C and D respectively. Green colour fades away slowly in two beakers. Identify the beakers.

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away

An Intiative by Sri Chaitanya

A and B

A and C

B and D

C and D

answer is A.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Concept- Ferrous sulphate is produced as a by-product in the production of copper sulphate and titanium pigment. The gas released has the distinct scent of burning sulphur. Crystals of ferrous sulphate contain water of crystallisation. Heat breaks down ferrous sulphate into ferric oxide, sulphur dioxide, and sulphur trioxide.
Generally speaking, a displacement reaction occurs when a more reactive element removes a less reactive element from its compounds. Example: The reaction between a sulphate solution and iron nails.
Iron is removed from the solution by magnesium and zinc because they are more reactive. Thus, in test tubes A and B, the green colour starts to disappear.
Zinc and magnesium are more effective at displacing iron from solutions. In test tubes A and B, the green colour consequently disappears.
Hence, option 1 is correct.

Watch 3-min video & get full concept clarity

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Books for IIT JEE

Best Books for NEET

How to Join IIT after 10th