$Δ G^{\circ}$ us T plot in Ellingham diagram slopes downward for the reaction :

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$Mg + \frac{1}{2} O_{2} \to MgO$

$2 Ag + \frac{1}{2} O_{2} \to {Ag}_{2} O$

$C + \frac{1}{2} O_{2} \to CO$

$CO + \frac{1}{2} O_{2} \to {CO}_{2}$

answer is C.

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Detailed Solution

$Δ G^{\circ}$ us T plot in the Ellingham diagram slopes downward for the reaction as follows, $C + \frac{1}{2} O_{2} \to CO$

Since the gas is used up during the reaction, the entropy decreases, which causes the term TS to have a positive value. Therefore, for the majority of the reduction reaction, slope S is positive.

For $C + \frac{1}{2} O_{2} \to CO$ , the oxidation process of carbon to carbon monoxide has a downward slope because the oxygen gas is consumed while the product created is also a gas, increasing the number of gaseous species and entropy.

Hence the correct option is C

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