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Q.

Gypsum is heated to 190^oC. The percentage loss in it’s weight is

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a

27%

b

36%

c

20.9%

d

15.7%

answer is C.

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Detailed Solution

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$\large \mathop {CaS{O_4}.2{H_2}O}\limits_{Gypsum} \;\xrightarrow[{i.e., > 120}]{{190^\circ C}}\;\mathop {CaS{O_4} + \;2{H_2}O}\limits_{Dead\;burnt\;gypsum}$
1 mole 2 moles loss
1 x 172 gr 2 x 18gr
100 gr ?
$\large \frac{{2 \times 18}}{{172}} \times 100 = \frac{{900}}{{43}} = 20.9\%$

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