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${}_{1}^{3}H or β$ - emitter which of the following is the correct nuclear disintegration reaction for ${}_{1}^{3}H$

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${}_{1}^{3}H \to β + {}_{1}^{1}H$

${}_{1}^{3}H \to β + {}_{1}^{3}{He}$

${}_{1}^{3}H \to β + {}_{2}^{4}{He}$

${}_{1}^{3}H \to β + {}_{1}^{2}H$

answer is B.

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Detailed Solution

${}_{1}^{3}H \to {}_{- 1}^{0}β (of low energy) + {}_{2}^{3}{He}$

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