Q.

H0 for a reaction , F2+2HCl2 HF +Cl2 is given as -352.8 kJ. Hf0 for HF is -268.3KJ mol-1, then calculate  Hf0kJ/mol of HCl

is -x then what is the value of x?

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answer is 92.

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Detailed Solution

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ΔHf(HF)o=268.3kJ ΔHrejection o=2ΔHf(HF)o2ΔHf(HCl)o352.18=2×(268.3)2xx=92.21kJmol1

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