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H₂ react with Cl₂ to form HCl as shown below $H_{2 (g)} + {Cl}_{2 (g)} \to 2 {HCl}_{(g)}$ When 22.4 L of H₂ is mixed with 11.2 L of Cl₂ at STP and upon reaction

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one mole of HCl is formed

11.2 L of H2 will remain unreacted

22.4 L of HCl is produced

All are correct

answer is D.

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