Q.

H2(g)+12O2gH2O(1); H=-286.2kJ; H2O(1)H(aq)++OH(aq)-; H=+57.3 kJ

Calculate the enthalpy of ionization of OH- in aqueous solution in kJ is -x what is the x value?

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answer is 228.

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Detailed Solution

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H2(g)+O2(g)+H2O(l)H2O(l)+H((aq.) ++OH(aq.) ); ΔH=[57.3+(286.2)]kJH2(g)+O2(g)H((aq.) )++OH((aq.) ; ΔH=228.9kJ228.5kJ

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