H2O2 is used as bleaching reagent because on dissociation it gives oxygen H2O2⟶H2O+12O2If "Chachi 420" used H2O2 solution to bleach her hair & she required 2.24 L O2 gas at 1 atm and 273 K. She has a H2O2 solution labelled as '5.6V' then what volume of such solution must she required to bleach her hair ?

volume of oxygen liberated=vol.strengh×vol.of H2O2 2.24=5.6×V ; volume of H2O2 =400ml

H2O2 is used as bleaching reagent because on dissociation it gives oxygen H2O2⟶H2O+12O2If "Chachi 420" used H2O2 solution to bleach her hair & she required 2.24 L O2 gas at 1 atm and 273 K. She has a H2O2 solution labelled as '5.6V' then what volume of such solution must she required to bleach her hair ?

volume of oxygen liberated=vol.strengh×vol.of H2O2 2.24=5.6×V ; volume of H2O2 =400ml

AI Mentor

Check Your IQ

Free Expert Demo

Try Test

Courses

Dropper NEET Course Dropper JEE Course Class - 12 NEET Course Class - 12 JEE Course Class - 11 NEET Course Class - 11 JEE Course Class - 10 Foundation NEET Course Class - 10 Foundation JEE Course Class - 10 CBSE Course Class - 9 Foundation NEET Course Class - 9 Foundation JEE Course Class -9 CBSE Course Class - 8 CBSE Course Class - 7 CBSE Course Class - 6 CBSE Course

Offline Centres

H₂O₂ is used as bleaching reagent because on dissociation it gives oxygen
$(H_{2} O_{2} ⟶ H_{2} O + \frac{1}{2} O_{2})$
If "Chachi 420" used H₂O₂ solution to bleach her hair & she required 2.24 L O₂ gas at 1 atm and 273 K. She has a H₂O₂ solution labelled as '5.6V' then what volume of such solution must she required to bleach her hair ?

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.

An Intiative by Sri Chaitanya

200 mL

300 mL

400 mL

500 mL

answer is C.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

$volume of oxygen liberated = vol . strengh \times vol . of H_{2} O_{2} 2.24 = 5.6 \times V; volume of H_{2} O_{2} = 400 ml$

Watch 3-min video & get full concept clarity

courses

No courses found

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Online Course for IIT JEE

Best Online Course for NEET

Best Online Course for CBSE

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Get Expert Academic Guidance – Connect with a Counselor Today!