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Q.

H₂O₂ reduces K₄[Fe(CN)₆]

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a

ln neutral solution

b

In acidic solution

c

In non-polar solvent

d

In alkaline solution

answer is B.

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Detailed Solution

When H₂O₂ reduces with K₄[Fe(CN)₆]. It is present in acidic solution.

$2 K_{4} [Fe (CN)_{6}] + H_{2} {SO}_{4} + H_{2} O_{2} \to 2 K_{3} [Fe (CN)_{6}] + K_{2} {SO}_{4} + 2 H_{2} O$

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H2O2 reduces K4[Fe(CN)6]