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Q.

$H_{2} O_{2}$ acts as a reducing agent in

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a

${Mn}^{2 +} + 2 H_{2} O_{2} \to {MnO}_{2} + 2 H_{2} O$

b

$2 {Fe}^{2 +} + 2 H^{+} + H_{2} O_{2} \to 2 {Fe}^{3 +} + 2 H_{2} O$

c

$2 NaOCl + H_{2} O_{2} \to 2 NaCl + H_{2} O + O_{2}$

d

${Na}_{2} S + 4 H_{2} O_{2} \to {Na}_{2} {SO}_{4} + 4 H_{2} O$

answer is C.

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Detailed Solution

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In $2 NaOCl + H_{2} O_{2} \to 2 NaCl + H_{2} O + O_{2}, H_{2} O_{2}$ acts as reducing agent.

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