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$H_{2} O_{2}$ decomposes with first order kinetics in a 3 lit. container. If the pressure developed in $10 \min$ . is $380 mm$ , the average rate at $27 ° C$ is

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$0.01 M \cdot \min^{- 1}$

$0.002 M \cdot \min^{- 1}$

$0.05 M \cdot \min^{- 1}$

$0.06 M \cdot \min^{- 1}$

answer is B.

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Detailed Solution

$n = \frac{pv}{RT} n = \frac{380 \times 3}{760 \times 0.082 \times 300} = 0.06$

$Average rate = \frac{concentration}{time} = \frac{0.02}{10} = 0.002 M - \min$

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