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$H_{2} O_{2}$ In its reaction with $K I O_{4}$ and $N H_{2} O H$ Respectively is acting as,

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Oxidising agent, Reducing agent.

Oxidising agent, Oxidising agent.

Reducing agent, Reducing agent.

Reducing agent, Oxidising agent.

answer is D.

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Detailed Solution

$K I O_{4} + H_{2} O_{2} \to K I O_{3} + H_{2} O + O_{2}$

$H_{2} O_{2}$ acts as reducing agent

$2 N H_{2} O H + H_{2} O_{2} \to N_{2} + 4 H_{2} O$

$H_{2} O_{2}$ acting as oxidizing agent

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