$H_{2} O_{2}$ restores the colour of old lead paintings, blackened by the action of $H_{2} S$ gas by :

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oxidising ${PbSO}_{3}$ to ${PbSO}_{4}$

converting ${PbO}_{2}$ to $Pb$

by oxidising $PbS$ to ${PbSO}_{4}$

converting ${PbCO}_{3}$ to $Pb$

answer is B.

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Detailed Solution

Hydrogen pereoxide restores the colour of old lead paintings, blackened by the action of hydrogen sulphide gas by sulfanylidenelead to Lead sulfate.

The oxidation of lead sulphate is as follows,

$PbO \overset{H_{2} S}{⟶} PbS \frac{H_{2} O_{2}}{4 (0)} {PbSO}_{4}$

Option B is correct.

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