${\mathrm{H}}_2\mathrm{O}$ is dipolar, whereas ${\mathrm{BeF}}_2$ is not. It is because

${\mathrm{H}}_2\mathrm{O}$ is angular, and ${\mathrm{BeF}}_2$ is linear

${\mathrm{H}}_2\mathrm{O}$ is linear, and ${\mathrm{BeF}}_2$ is angular

${\mathrm{H}}_2\mathrm{O}$ involves H-bonding, whereas ${\mathrm{BeF}}_2$ is discrete molecule

the electronegativity of F is greater than O