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Q.

$H_{2} S$ , a toxic gas with rotten egg like smell, is used for the quantitative analysis. If the solubility of $H_{2} S$ in water at STP is 0.2 m, then Henry’s law constant for $H_{2} S$ in water at 273 K is (use $P_{H_{2} S}$ at STP = 1 bar)

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a

$2.78 \times 10^{7} P a$

b

$3.6 \times 10^{8} P a$

c

$5.0 \times 10^{5} P a$

d

$5.0 \times 10^{8} P a$

answer is D.

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Detailed Solution

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$P = K_{H} . X \Rightarrow 1 b a r = K_{H} \times \frac{0.2}{0.2 + \frac{1000}{18}}, ∴ K_{H} = 277.78 b a r = 2.78 \times 10^{7} P a$

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H2S, a toxic gas with rotten egg like smell, is used for the quantitative analysis. If the solubility of H2S in water at STP is 0.2 m, then Henry’s law constant for H2S in water at 273 K is (use PH2S at STP = 1 bar)