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$H_{2} S$ is more acidic than $H_{2} O$ ,due to

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$\bar{O} - H$ bond is stronger than $S - H$ bond

$\bar{O} - H$ bond is weaker than $S - H$ bond

$O$ is more electronegative than $S$

None of these

answer is B.

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Detailed Solution

The acidity of hydrides of VI group elements increase from top to bottom as the bond strength $X - H$ decrease from top to bottom decrease from top to bottom

$H_{2} O < H_{2} S < H_{2} Se < H_{2} Te$

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