H₂SO₄ is labelled as 9.8% by weight. Specific gravity of H₂SO₄ is 1.8. The volume of the acid to be taken to prepare 1000 ml of 0.18M solution is

Molarity=$\frac{(\mathrm{w}/\mathrm{w})\%\times \mathrm{specific} \mathrm{gravity}\times 10}{\mathrm{Molar} \mathrm{mass}}$

$\mathrm{M}=\frac{9.8\times 1.8\times 10}{98}=1.8\mathrm{M}$

The volume of the acid to be taken to prepare 1000 ml of 0.18M solution is=V₁

$$\begin{gathered} {\mathrm{M}}_1{\mathrm{V}}_1={\mathrm{M}}_2{\mathrm{V}}_2 \\ 1.8\times {\mathrm{V}}_1=1000\times 0.18 \\ {\mathrm{V}}_1=100\mathrm{ml} \end{gathered}$$