${\displaystyle H_{2}S{O}_4}$ is labelled as 9.8% by weight. Specific gravity of${\displaystyle H_{2}S{O}_4}$ is 1.8. The volume of the acid to be taken to prepare 1000 ml of 0.18M solution is

w/w% of H₂SO₄ = 9.8%

sp.gravity of H₂SO₄ = 1.8

The amount of acid required to make 1000ml of 0.18M sol.

V_iM_i = V_fM_f, according to the dilution rule

V_i(1.8) = 1000 (0.18)

V_i = 100ml

Hence the answer is (B)100 ml