H3PO4 + 2KOH → K2HPO4 + 2H2O Based on the above reaction equivalent weight of H3PO4 is

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H₃PO₄ + 2KOH → K₂HPO₄ + 2H₂O Based on the above reaction equivalent weight of H₃PO₄is

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196

32.67

answer is C.

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H₃PO₄ + 2KOH → K₂HPO₄ + 2H₂O

In this reaction only two H-atoms of H₃PO₄ are replaced by metal atoms. H₃PO₄ acts like a dibasicacid

$\large \therefore EW = \frac{MW}{2}$

$\large EW = \frac{98}{2}$

= 49

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