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$H_{3} {PO}_{4} (98 g {mol}^{- 1})$ is 98% by mass of solution. If the density is 1.8 g/ml, the molarity is

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18 M

36 M

54 M

0.18 M

answer is A.

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Detailed Solution

$Molarity = \frac{(W / W) % \times d \times 10}{Molecular weight} = \frac{10 \times 1 .8 \times 98}{98} = 18 M$

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