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Haemoglobin contains 0.33% iron (Fe = 56). The molecular weight of haemoglobin is 68000. The number of iron atoms in one molecule of haemoglobin is

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answer is C.

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Detailed Solution

Given, 100g of haemoglobin contains 0.33g. of iron

Mass of 'Fe' present in 68000g of haemoglobin = $\frac{68000}{100} \times 0.33 = 224.4 g$

No. of 'Fe' atoms in one molecule of haemoglobin = $\frac{224.4}{56} = 4$

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