Haemoglobin contains 0.33% iron (Fe=56). The molecular weight of haemoglobin is 68000. The number of iron atoms in one molecule of haemoglobin is

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Haemoglobin contains 0.33% iron (Fe=56). The molecular weight of haemoglobin is 68000. The number of iron atoms in one molecule of haemoglobin is

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answer is C.

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Detailed Solution

Given, Molar mass of $F e = 56 g$

Molecular weight of haemoglobin = 68000

% of Fe present in haemoglobin = 0.33%

$W e i g h t o f F e = \frac{33}{100} \times 68000 = 224.4 g {m o l}^{- 1}$

Moles of $F e = 224.4 / 56 = 4$

So, the number of iron present in haemoglobin is 4.

Therefore, option C is correct.

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