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Q.

Haemoglobin contains 0.33% iron (Fe=56) The molecular weight of haemoglobin is 68000. How many number of iron atoms are in one molecule of haemoglobin?

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answer is 4.

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Detailed Solution

$w e i g h t o f F e = \frac{0.33}{100} \times 67200 = 221.8$

$Therefore no of Fe, \frac{221.8}{55.8} = 4$

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