Hailstone at 0°C falls from a height of 1 km on an insulating surface converting whole of its kinetic energy into heat. What part of it will melt? ( $g = 10 \frac{m}{s^{2}}$ )

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$\frac{1}{33}$

$\frac{1}{8}$

$\frac{1}{33} \times 10^{- 4}$

All of it will melt

answer is A.

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Detailed Solution

Energy required for melting = Loss in potential energy

$\Rightarrow J \times m' L = m g h \Rightarrow 4.18 \times (m' \times 80 \times 10^{- 3}) = m \times 10 \times 1000 \Rightarrow \frac{m'}{m} = \frac{1}{33} [A s L = 80 \times 10^{- 3} c a l o r i e / k g]$

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