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Q.

Half-lives of two radioactive elements A and B are 20 minutes and 40 minutes, respectively. Initially, the samples have equal number of nuclei. After 80 minutes, the ratio of decayed numbers of A and B nuclei will be

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a

1 : 4

b

5 : 4

c

1 : 16

d

4 : 1

answer is A.

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Detailed Solution

$N_{d e c a y e d} = N o (1 - e^{\frac{t}{t_{1 / 2}}})$
$\frac{N_{A}}{N_{B}} = \frac{5}{4}$

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