Haloform test is shown by the compound

2- Because it can easily be converted into acetone $\left({\mathrm{CH}}_3{\mathrm{OCCH}}_3\right)$, which has a methyl keto group, propanol $\left({\mathrm{CH}}_3{\mathrm{OHCHCH}}_3\right)$ is likely to pass the haloform test. Haloform test is provided by substances with methyl keto group.