$HA + {OH}^{-} \to H_{2} O + A^{-} + Q_{1} KJ$ $H^{+} + {OH}^{-} \to H_{2} O + Q_{2} KJ$
The enthalpy of dissociation of the weak acid 'HA' is

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$Q_{1} - Q_{2}$

$- (Q_{1} + Q_{2})$

$Q_{1} + Q_{2}$

$Q_{2} - Q_{1}$

answer is C.

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Detailed Solution

: $HA + {OH}^{-} \to H_{2} O + A^{-} + q_{1} k J \dots .$ . (1)

$H^{+} + {OH}^{-} \to H_{2} O + q_{2} kJ$

$H_{2} O \to H^{+} + {OH}^{-} - q_{2} kJ$

Adding ${eq}^{n} (1) (2)$ , we have

$HA + {OH}^{-} + H_{2} O \to H_{2} O + A^{-} + H^{+} + {OH}^{-} + (q_{1} - q_{2}) kJ$

Hence the enthalpy of dissociation of HA is $(q_{2} - q_{1}) kJ$ .

Hence the correct answer is (C) $Q_{2} - Q_{1}$ .

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