Hardness of water is 200 ppm. The normality and molarity of CaCO3 in water x×10−3N,y×10−3M. Respectively. Find x+y=?

=200×1000100×106=2×10−3M N=n×M=2×2×10−3=4×10−3N

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Hardness of water is 200 ppm. The normality and molarity of $C a C O_{3}$ in water $x \times 10^{- 3} N, y \times 10^{- 3} M$ . Respectively. Find $x + y = ?$

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answer is 6.

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$= \frac{200 \times 1000}{100 \times 10^{6}} = 2 \times 10^{- 3} M N = n \times M = 2 \times 2 \times 10^{- 3} = 4 \times 10^{- 3} N$

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