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Q.

HCF of 6,72 and 120 is

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a

6

b

2

c

3

d

1

answer is A.

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Detailed Solution

Concept: The numbers that we have are 6, 72, and 120. HCF, as we are all aware, is the result of the provided numbers' lowest power of prime factors. Find the factors of all the integers first using the prime factorization method. The highest common factor, or HCF, is then obtained by multiplying the lowest powers of the common factors.
The following figures are available: 6, 72, and 120.
Write the natural numbers that are provided now as the product of their prime factors. Multiply all the common prime factors with the lowest degree to get the maximum common factor (power) .
Now, using the prime factorization method, we can determine the numbers' prime factors:
6=2×372=2×2×2×3×3
120=2×2×2×3×5
Therefore,

2^{1}

,

3^{1}

is the lowest degree of shared prime factors.
Therefore,

2^{1} \times 3^{1}

=6 is the result of the lowest degree of prime components.
6 is the HCF of 6, 72, and 120 as a result.
Hence, the answer is option 1.

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