HCI is produced in the stomach, which can be neutralized by Mg(OH)₂ in the form of milk of magnesia. How much Mg(OH)₂ is required to neutralize one mole of stomach acid?

$\mathrm{Mg}(\mathrm{OH}{)}_2+2\mathrm{HCl}\to {\mathrm{MgCl}}_2+2{\mathrm{H}}_2\mathrm{O}$
No. of moles of Mg(OH)₂ required for 2 moles of HCI = 1
No. of moles of Mg(OH)₂ required for 1 mole of HCI = 0.5
Mass of 0.5 moles of Mg(OH)₂ = 58.33 x 0.5 = 29.16 g