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HCl gas is passed through a saturated solution of $NaCl$ containing ${MgCl}_{2} & {CaCl}_{2}$ impurities. NaCl is precipitated during this process which is best explained by

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More ionic character in NaCl

High lattice enthalpy of NaCl

Lesser solubility of NaCl compared to ${MgCl}_{2} and {CaCl}_{2}$

High Polarising Power of ${Na}^{+}$ ion

answer is C.

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Detailed Solution

Solubility of NaCl is lesser than that of ${CaCl}_{2} & {MgCl}_{2}$ . When HCl gas is passed through the mixture, $[{Cl}^{-}]$ increases, Ionic product of NaCl exceeds its solubility product easily. Thus it gets precipitated

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