Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

HCO , HO=O , HC=O respectively are 1070, 498 and 741KJ/mol. Then ΔH for CO+12O2CO2[in KJ] is

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya

a

788

b

394

c

-163

d

-81.5

answer is A.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

\begin{array}{l} {\Delta _r}{H^o} = B{E_{C \equiv O}} + \frac{1}{2}B{E_{O = O}}[ - 2B{E_{C = O}}]\\\\ \,\,\,\,\,\,\,\,\,\,\,\,\,\, = \,1070 + {\textstyle{{498} \over 2}} - [2 \times 741]\\\\ \,\,\,\,\,\,\,\,\,\,\,\,\,\, = - 163KJ\\ \,\,\,\,\,\,\,\,\,\,\,\,\,\, \end{array}

 

Watch 3-min video & get full concept clarity
score_test_img

courses

No courses found

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Get Expert Academic Guidance – Connect with a Counselor Today!

best study material, now at your finger tips!

  • promsvg

    live classes

  • promsvg

    progress tracking

  • promsvg

    24x7 mentored guidance

  • promsvg

    study plan analysis

download the app

gplay
mentor

Download the App

gplay
whats app icon
personalised 1:1 online tutoring