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Heat capacity (CV) of an ideal gas is X KJ/ mole/K. To rise its temperature from298 K to 318 K, heat to be supplied per 10g gas will be (in KJ) [MW =16]

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a
16X
b
6.25X
c
32 X
d
12.5X

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detailed solution

Correct option is D

heat supplied (qv) = nCv(T2-T1) = 1016× X ×20

= 12.5 X kJ/mole

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