Heat energy absorbed by a system is going through a cyclic process as shown in figure, is

In cyclic process,  $\mathrm{\Delta }U=0$

$\therefore \text{ Heat absorbed }=\text{ Work done }=\text{ Area under }p-V\text{ graph }$

$=\left(\pi \right)\left(R_x\right)\left(R_y\right)$

$=\pi \left(10\times {10}^3\right)\left(10\times {10}^{-3}\right)={10}^2\pi \mathrm{J}$