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Heat energy of 743J is needed to raise the temperature of 5 moles of an ideal gas by 2K at constant pressure. How much heat is needed to raise the temperature of the same mass of the gas by 2K at constant volume. (make up the answer to the nearest integer)
( $R = 8.314 J . K^{- 1} m o l e^{- 1}$ )

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answer is 660.

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Detailed Solution

$ΔH = 743 J for 5 mole of gas$
$\begin{array}{l} ΔH = ΔU + n \cdot R \cdot ΔT \\ ΔU = 659 .86 for 5 mole of gas \\ = 65 .986 for 5 mole of gas \\ = 66 J \end{array}$

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