Q.

Heat of formation of 2 mol of NH3(g) is -90 kJ; bonding energies of H – H and N – H bonds are 435 kJ and  390 kJmol1 respectively. The value of the bond energy of NN will be

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a

945 kJ/mole

b

872.5 KJ

c

-872.5 KJ

d

-945 kJ

answer is D.

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Detailed Solution

ΔH=BE reactan tsBE products 

N2+3H22NH3

90kJ=[x+3(435)][6×390] x=945kJ

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