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Q.

Heat of neutralization for the reaction NaOH + HCl ® NaCl + H  O is -57.1kJ mole-1 . The heat released when 0.25 moles of NaOH is treated with 0.25 moles of HCl is

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a

22.5 kJ

b

57.1 kJ

c

14.3 kJ

d

28.6 kJ

answer is C.

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Detailed Solution

NaOH + HCl ® NaCl + H2O ; DH = -57.1kJ

Per 1mole →-57.1kJ

0.25 mole = -57.1x0.25 = 14.3kJ

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