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Q.

Henry thinks that a mole contains 6.023 × 10²⁴ molecules. Hence the mass of Henry’s mole of Nitrogen is

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a

2.8g

b

0.28g

c

28g

d

280g

answer is C.

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Detailed Solution

According Henry, Avagadro's number =6.023 x 10²⁴

6.023 x 10²³molecules of N₂ weight 28g

6.023 x 10²³molecules of N₂ weight 'X'g

\large X = \frac{6.023 \times 10^{24}}{6.023 \times 10^{23}} \times 28 = 280g

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