Q.

Henry’s constant (in K.bar) for four gases α,β,γ and  δ in water at 298K is given below:

gases

α

β

γ

δ

KH

50

2

2×10-5

0.5

(density of water =103kg/m3 at 298K)

This table implies that

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a

'α' has the highest solubility in water at a given pressure.

b

Solubility of 'γ' at 308K is lower than at 298K

c

The pressure of 55.5 molal solution of 'γ' is 1 bar

d

The pressure of 55.5 molal solution of 'δ' is 250 bar

answer is D.

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Detailed Solution

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A) From Henry’s law,  p=KHXX=pKHXα1KH(p=constant)

Higher the value of KH smaller will be the solubility of the gas, so 'γ' is more soluble.

B)Though solubility of gases will decrease with increase in temp

C)Pγ=KHXγ=2×10555.555.5+100018=105K.bar=102bar

D)Pδ=KHXδ=0.555.555.5+100018=0.5×0.5=0.25Kbar=250bar

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