In BH3 unit H- is the nucleophile. It add as per Anti-Markonikov's productR−CH=CH2→H2O2BH3R−CH2−CH2−OHHere R= isopropyl group.

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Here product 'A' is

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3 - methyl - 2 - butanol

2 - methyl - 2 - butanol

2 - methyl - 1 - butanol

3 - methyl - 1 - butanol

answer is B.

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Detailed Solution

In BH₃ unit H^- is the nucleophile. It add as per Anti-Markonikov's product
$R - CH = {CH}_{2} \to_{H_{2} O_{2}}^{{BH}_{3}} R - {CH}_{2} - {CH}_{2} - OH$

Here R= isopropyl group.

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