Here X and Y are
${CH}_{2} = {CH}_{2} \overset{{Cl}_{2} / {CCl}_{4}}{\to} X$
${CH}_{2} = {CH}_{2} \overset{{Cl}_{2} / H_{2} O}{\to} Y$

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${ClCH}_{2} {CH}_{2} Cl, {ClCH}_{2} {CH}_{2} Cl$

${ClCH}_{2} {CH}_{2} Cl, {ClCH}_{2} {CH}_{2} OH$

${Cl}_{2} C = {CCl}_{2}, ClCH = CHCl$

${Cl}_{2} C = {CCl}_{2}, {ClCH}_{2} {CH}_{2} OH$

answer is B.

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Detailed Solution

Ethylene upon reaction with chlorine in carbon tetra chloride produces a reduction

product 1,2-dichloroethane

${CH}_{2} = {CH}_{2} \overset{{Cl}_{2} / {CCl}_{4}}{\to} {ClCH}_{2} {CH}_{2} Cl$

Ethylene upon shaken with chlorine in presence of water produces a reduction product

2-chloroethanol

${CH}_{2} = {CH}_{2} \overset{{Cl}_{2} / H_{2} O}{\to} {ClCH}_{2} {CH}_{2} OH$

Hence the correct option is (B).

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