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Q.

$HF$ is a weak acid but on addition of ${SbF}_{5},$ it becomes a very strong acid. The number of 90° angles in the anionic part of the product is ___.

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answer is 12.

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Detailed Solution

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Anionic part is ${[S b F_{6}]}^{-}, s p^{3} d^{2}$ hybridisation So, 90 degree bond angles = 12

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